(x^2)/(2)-5x=-8x

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Solution for (x^2)/(2)-5x=-8x equation:


x in (-oo:+oo)

(x^2)/2-(5*x) = -8*x // + -8*x

(x^2)/2-(5*x)-(-8*x) = 0

(x^2)/2-5*x+8*x = 0

1/2*x^2+3*x = 0

DELTA = 3^2-(0*1/2*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-3)/(1/2*2) or x = (-9^(1/2)-3)/(1/2*2)

x = 0 or x = -6

x in { -6, 0 }

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